Geany run script8/31/2023 I just experienced this this oddity on CentOS 6 after cat > shScript.sh (paste, Z) then editing the file in KWrite.Oddly there was no discernible instance (ps -ef) of the script executing.My quick work around was simply to cp shScript.sh shScript2. I have even tried to run postgres*.bin from ~/ with no success. Dont know the cause but I can contribute a quick and easy work around. I gave chmod x permission to postgres*.bin before I ran it. Lrwxrwxrwx 1 root root 4 Nov 14 12:29 sh -> bash* There is a link sh -> bash* at /bin # ls -l sh The first line of getlocales.sh has #!/bin/sh in it What I have already checked (looking in this and other forums) karel at 12:08 8 While editing using vim, hit Esc and type :sh and Enter, when done hit Ctrl-D and you'll get back to your vim session. bin/sh: bad interpreter: Permission denied bin/sh: /tmp/postgresql_installer/getlocales.sh: geanyrunscript.sh: sudo./untitled: not found-(program exited with code: 127) Press return to continue Please help,I really dont know whats the problem. I pressed execute and new window appeared, it said. Error:Įrror running /tmp/postgresql_installer/getlocales.sh : I wanted to try it out so I copied program from the internet. Join these companies and the four million developers who are already building, running and debugging with Fiddler. When I run it as root at the command line typing this. You can even open a file in Geany, directly from the command line. Or, from the terminal, you can type sudo geany. Once installed, you can run Geany by going to the 'Start' menu, and looking under the 'Programming' tab. When you press Execute, Geany executes the terminal specified in Edit -> Preferences -> Tools, replacing c with the Execute command set in Build -> Set Build Commands. The command set in the 'Set Build Commands' dialog is run in a script to ensure the terminal stays open after execution completes. Execute will run the corresponding executable file, shell script or interpreted script in a terminal window. I was also told that this file works OK and has already successfully performed installations of Postgres on many other Linux (CentOS) systems running OpenClinica. Once your script has run its course, be kind to the next process that might use your GPIOs by cleaning up after yourself. Check Geany Build configuration to adjust the path and which version of python is launched. The file looks like postgresql-8.4.1-1-linux-圆4.bin. I am working on a particular project (OpenClinica) for a client and I need to install Postgresql version 8.4 (old version, I know) directly from a. This mistake actually appears somewhat frequently on Stack Overflow, but it's rather hard to search for.I have already looked at similar posts in this forum related to bad interpreter and denied permissions, and was unable to find a solution to this problem. You could also phrase this as "loop while it's not ( equal to c or equal tol` or …)", in which case you could loop while !( choix = 'c' || choix = 'l' || choix = 'e' || choix = 's' ) That is, you continue looping as long as it's not c, and it's not l_, and it's not e, and it's not s. If you're trying to loop until the user puts in one of the designated characters, you need to loop while (choix != 'c') & (choix != 'l') & (choix != 'e') || (choix != 's') The same thing would happen if the user had typed e, which is supposed to be one of your options. Then the first part (choix != 'c') will be true and you'll quit. Open any application or terminal, such as geany 3, press the Shift key to switch to. You end when (choix != 'c') || (choix != 'l') || (choix != 'e') || (choix != 's')īut every character is not the same as at least one of c, l, e, or s. Run a swayidle script like the one above to turn off your monitors. However, once you get that worked out, you'll have some problems ending your loop. Or you could use a function like putchar and do putchar(choix) Instead, you should either pass printf a string with a format directive that expects a char, such as in printf("%c", choix) It's treating that character as a pointer, but it's not going to be a valid pointer, and it's pointing somewhere very low in memory that you should not be trying to access. Printf's argument needs to be a string, but you're passing it a char in printf(choix)
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